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ОтвеченоEntitySQL: Ordering a collection in the Select

  • 2 июля 2009 г. 11:28duke.ua Медали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     
    Imagine there's an entitySet FirstEntitySet that has a reference 1..N to another (AnotherEntities). And you want to get the following ESQL:
    SELECT
    
    
    
     it.AnotherEntities, it.Name
    FROM
    
    
    
     ctx.FirstEntitySet as
    
    
    
     it
    
    
    in other words you want some fields from the FirstEntitySet and a field that would be a collection of objects.

    The question is: how to make that collection ordered? What to write in ORDER BY ?
    this question is answered, however another one raised lower in the thread...
    • Измененоduke.ua 3 июля 2009 г. 11:05
    • Измененоduke.ua 3 июля 2009 г. 14:15
    •  

Ответы

  • 6 июля 2009 г. 23:37Kati Iceva - MSFTМодераторМедали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     Отвечено

    Hi,

    This seems to be a provider issue. I tried a similar query over SQL Server using our provider and it produces the correct results. Also the output Command Tree based on which a provider generates the SQL looks correct too.

    And yes, I agree with your observation.   Another option is to prefix to order keys with `UnionAll1` as we do in our SQL Generation in SQL Client.

     

    Thanks,
    Kati


    This posting is provided "AS IS" with no warranties, and confers no rights.
    • Помечено в качестве ответаduke.ua 7 июля 2009 г. 6:29
    •  

Все ответы

  • 2 июля 2009 г. 18:26Kati Iceva - MSFTМодераторМедали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     Предложенный ответ

    Hi,

    You should be able to write it as

    SELECT (SELECT VALUE A

            FROM it.AnotherEntities AS A

            ORDER BY A.OrderingProperty), it.Name

    FROM ctx.FirstEntitySet as it

     

    I hope that helps.

    Thanks,

    Kati


    This posting is provided "AS IS" with no warranties, and confers no rights.
    • Предложено в качестве ответаKati Iceva - MSFTМодератор2 июля 2009 г. 21:44
    • Снята пометка об ответеduke.ua 3 июля 2009 г. 11:03
    • Помечено в качестве ответаduke.ua 3 июля 2009 г. 10:27
    •  
  • 3 июля 2009 г. 10:28duke.ua Медали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     
    select value ! i thought i was missing something obvious :)
  • 3 июля 2009 г. 10:51duke.ua Медали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     С кодом
    well yeah, the output isn't actually ordered. looks like a bug, maybe in EF, maybe in data provider's methods to parse out native sql...
    ----------------------------------------------------------------
    the reason it's more complicated than one related set of entities. it's two! Thus there's a Union All in native sql

    adding the ordering adds this to native SQL:
    ,
    NULL AS `C10`
    (in the first part of union all)
    ,
    `Extent4`.`R_ID` AS `R_ID1`
    
    (in the second part of union all)
    ,
    `C10` ASC 
    (in the order by part of union all)

    however! there's nothing in the select part of union all actually there is a C10, which is a completely different field ! just adding a
    ,
           UnionAll1.C10           AS C16
    (in the select part of union all)

    and changing the ordering part to
    ,
    `C16` ASC
    would solve the problem.

    so that's a bug. question is where and if there could be a workaround?
    • Измененоduke.ua 3 июля 2009 г. 11:03
    •  
  • 6 июля 2009 г. 6:42Diego B VegaMSFT, МодераторМедали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     
    Hello Duke,

    Your description of the issue has become difficult to follow. Would it be possible for you to provide the following:

    1. Full eSQL version of the actual query
    2. Whole native SQL translation?
    3. Also, what data provider are you using?

    Not sure this will be sufficient information, but it would help us start.

    Thanks,
    Diego
    This posting is provided "AS IS" with no warranties, and confers no rights.
  • 6 июля 2009 г. 7:51duke.ua Медали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     С кодом
    1)
    SELECT 
    (SELECT value a FROM c1.founders as a
     order by a.FOUNDER_ID) as data_old,
    (SELECT value b FROM c1.na.na_founders as b
     order by b.FOUNDER_ID) as data_new
    FROM Entities.mainSet as c1
    WHERE c1.main_id = @main_id
    
    2)
    SELECT
    `UnionAll1`.`MAIN_ID` AS `C1`, 
    `UnionAll1`.`MAIN_ID1` AS `C2`, 
    `UnionAll1`.`C2` AS `C3`, 
    `UnionAll1`.`C1` AS `C4`, 
    `UnionAll1`.`C3` AS `C5`, 
    `UnionAll1`.`FOUNDER_ID` AS `C6`, 
    `UnionAll1`.`C4` AS `C7`, 
    `UnionAll1`.`FOUNDER_NAME` AS `C8`, 
    `UnionAll1`.`MAIN_ID2` AS `C9`, 
    `UnionAll1`.`FOUNDER_ID1` AS `C10`, 
    `UnionAll1`.`C5` AS `C11`, 
    `UnionAll1`.`C6` AS `C12`, 
    `UnionAll1`.`C7` AS `C13`, 
    `UnionAll1`.`C8` AS `C14`, 
    `UnionAll1`.`C9` AS `C15`
    FROM ((SELECT
    CASE WHEN (`Extent2`.`FOUNDER_ID` IS  NULL) THEN (NULL)  ELSE (1) END AS `C1`, 
    `Extent1`.`MAIN_ID`, 
    `Extent1`.`MAIN_ID` AS `MAIN_ID1`, 
    1 AS `C2`, 
    CASE WHEN (`Extent2`.`FOUNDER_ID` IS  NULL) THEN (NULL)  ELSE (1) END AS `C3`, 
    `Extent2`.`FOUNDER_ID`, 
    CASE WHEN (`Extent2`.`FOUNDER_ID` IS  NULL) THEN (NULL)  ELSE (1) END AS `C4`, 
    `Extent2`.`FOUNDER_NAME`, 
    `Extent2`.`MAIN_ID` AS `MAIN_ID2`, 
    `Extent2`.`FOUNDER_ID` AS `FOUNDER_ID1`, 
    NULL AS `C5`, 
    NULL AS `C6`, 
    NULL AS `C7`, 
    NULL AS `C8`, 
    NULL AS `C9`, 
    NULL AS `C10`
    FROM `main` AS `Extent1` LEFT OUTER JOIN `founders` AS `Extent2` ON `Extent1`.`MAIN_ID` = `Extent2`.`MAIN_ID`
     WHERE `Extent1`.`MAIN_ID` = 11111) UNION ALL (SELECT
    2 AS `C1`, 
    `Extent3`.`MAIN_ID`, 
    `Extent3`.`MAIN_ID` AS `MAIN_ID1`, 
    1 AS `C2`, 
    NULL AS `C3`, 
    NULL AS `C4`, 
    NULL AS `C5`, 
    NULL AS `C6`, 
    NULL AS `C7`, 
    NULL AS `C8`, 
    1 AS `C9`, 
    `Extent4`.`FOUNDER_ID`, 
    1 AS `C10`, 
    `Extent4`.`FOUNDER_NAME`, 
    `Extent4`.`MAIN_ID` AS `MAIN_ID2`, 
    `Extent4`.`FOUNDER_ID` AS `FOUNDER_ID1`
    FROM `main` AS `Extent3` INNER JOIN (`na_founders` AS `Extent4` INNER JOIN (`na` AS `Extent5` LEFT OUTER JOIN `main` AS `Extent6` ON `Extent5`.`MAIN_ID` = `Extent6`.`MAIN_ID`) ON `Extent4`.`MAIN_ID` = `Extent5`.`MAIN_ID`) ON `Extent3`.`MAIN_ID` = `Extent5`.`MAIN_ID`
     WHERE `Extent3`.`MAIN_ID` = 11111)) AS `UnionAll1`
     ORDER BY 
    `MAIN_ID` ASC, 
    `MAIN_ID1` ASC, 
    `C1` ASC, 
    `FOUNDER_ID1` ASC, 
    `C10` ASC 
    

    3) the only official mySQL provider that works with EF

    4) here's the difference that would make it work correctly that i was trying to ambigiously describe in previous message: 1 2
  • 6 июля 2009 г. 23:37Kati Iceva - MSFTМодераторМедали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     Отвечено

    Hi,

    This seems to be a provider issue. I tried a similar query over SQL Server using our provider and it produces the correct results. Also the output Command Tree based on which a provider generates the SQL looks correct too.

    And yes, I agree with your observation.   Another option is to prefix to order keys with `UnionAll1` as we do in our SQL Generation in SQL Client.

     

    Thanks,
    Kati


    This posting is provided "AS IS" with no warranties, and confers no rights.
    • Помечено в качестве ответаduke.ua 7 июля 2009 г. 6:29
    •  
  • 7 июля 2009 г. 6:29duke.ua Медали пользователяМедали пользователяМедали пользователяМедали пользователяМедали пользователя
     
    I see. Thank You.