tool tips over selected row in DataGrid (not Datagridview)

Question

I am trying to make it so that when the user mouses over a select set of cells (they are all in the same column) each row would display a different tooltip outcome.

I cannot really figure this out. with DataGrid how can I say mouseOver on each row and give row specific data???

Answer 1

Hi：）

Show us your screenshot as well as your existing codes……

---

   QQ我：
下载MSDN桌面工具(Vista,Win7)
我的博客园
慈善点击，点击此处

Answer 2

Hi jambox5,

According to my knowledge, we can't set different tool tip value for each cell in DataGrid as DataGridCell doesn't contains ToolTipText proeprty.

If you want to use tool tip, I suggest you use DataGridView Control instead.

Otherwise, you need to show tool tip by code, check the work around below.

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void Form1_Load(object sender, EventArgs e)
    {
        DataGrid dg = new DataGrid();
        dg.Size = new Size(300, 200);
        DataTable dt = new DataTable();
        dt.Columns.Add("A");
        dt.Columns.Add("B");
        dt.Rows.Add("a", "b");
        dt.Rows.Add("a1", "b1");
        dg.DataSource = dt;

        dg.MouseMove += new MouseEventHandler(dg_MouseMove);
        this.Controls.Add(dg);
        toolTip.ShowAlways = true;
    }

    ToolTip toolTip = new ToolTip();
    int X;
    int Y;
    bool b = false;
    public void dg_MouseMove(object sender, MouseEventArgs e)
    {
        DataGrid dg = sender as DataGrid;
        if (dg == null)
            return;
        if (e.X != X || e.Y != Y)
        {
            if (b == true)
            {
                toolTip.Hide(dg);
                b = false;
            }
            X = e.X;
            Y = e.Y;
        }

        if (!b)
        {
            DataGrid.HitTestInfo info = dg.HitTest(X, Y);
            if (info.Type == DataGrid.HitTestType.Cell)
            {
                b = true;
                toolTip.Show(string.Format("row index: {0}, column index: {1}", info.Row, info.Column), dg, new Point(X, Y));
            }
        }
    }
}

Best Regards,

---

Bob Wu [MSFT]
MSDN Community Support | Feedback to us