Object reference not set to instance of an object error SharePoint DateTimeControl selectedDate

Question

Hi,

I have a DateTimeControl and in a GridView. I want to display selectedDate inside the textbox after click on a button. But OnClick event of the button I got 'Object reference not set to instance of an object' error. Below are the codes:

 protected void Test_Click(object sender, EventArgs e)
    {
        DateTimeControl DateAndTimeIn = gvRoom.FindControl("SPTimeIn") as DateTimeControl;

        txtTest.Text = DateAndTimeIn .SelectedDate.ToString();
    }

Any help on this issue would be appreciated. Thanks

---

wawa87

Answer 1

Hi,

I have a DateTimeControl and in a GridView. I want to display selectedDate inside the textbox after click on a button. But OnClick event of the button I got 'Object reference not set to instance of an object' error. Below are the codes:

 protected void Test_Click(object sender, EventArgs e)
    {
        DateTimeControl DateAndTimeIn = gvRoom.FindControl("SPTimeIn") as DateTimeControl;

        txtTest.Text = DateAndTimeIn .SelectedDate.ToString();
    }

Any help on this issue would be appreciated. Thanks

---

wawa87

Any feedback on this item yet?

---

wawa87

Answer 2

Hello wawa87,

have you checked that the value of DateAndTimeIn object,

i think you are getting null value,

can you please confirm this?

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Hiren Patel | Please click "Propose As Answer" if this post solves your problem or "Vote As Helpful" if this post has been useful to you.

Answer 3

I've tried to check either the control return null value but I still getting the same error message.

DateTimeControl DateAndTimeIn = gvRoom.FindControl("SPTimeIn") as DateTimeControl;
        if (DateAndTimeIn .SelectedDate != null)
        {
            Response.Write("not null");
            //txtTest.Text = DateAndTimeIn .SelectedDate.ToString();
        }
        else
        {
            Response.Write("null");
        }

---

wawa87

Answer 4

Yes the error will come because of the value of DateAndTimeIn  is null and in if condition you are trying to access the property SelectedDate thats why you are receiving error.

i want to know that where you have put that DataTime control in gridview , header template or item tempate ?

if possible then also provide the source code for the gridview for .aspx or .ascx file and also code behind to it will easy to short out the issue.

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Hiren Patel | Please click "Propose As Answer" if this post solves your problem or "Vote As Helpful" if this post has been useful to you.

Answer 5

Here you can how to find the control if have put it in item template of the grid view

<asp:GridView ID="grd" runat="server" AutoGenerateColumns="False" 
			onrowdatabound="grd_RowDataBound">
			<Columns>
				<asp:TemplateField>
					<HeaderTemplate>
						<table>
							<tr>
								<td>
									<asp:Label ID="lblFnameHeader" runat="server"></asp:Label>
								</td>
								<td>
									<asp:Label ID="lblLNameHeader" runat="server"></asp:Label>
								</td>
								<td>
									<asp:Label ID="lblOperation" runat="server" Text="Operation"></asp:Label>
								</td>
							</tr>
						</table>
					</HeaderTemplate>
					<ItemTemplate>
						<table>
							<tr>
								<td>
									<asp:Label ID="lblFname" runat="server" Text='<%# Bind("Fname") %>'></asp:Label>
								</td>
								<td>
									<asp:Label ID="lblLName" runat="server" Text='<%# Bind("Lname") %>'></asp:Label>
								</td>
								<td>
									<asp:Button ID="btn" runat="server" Text='<%# Bind("Fname") %>' />
								</td>
							</tr>
						</table>
					</ItemTemplate>
				</asp:TemplateField>
			</Columns>
		</asp:GridView>

code behind

public void BindGrid()
	{
		DataTable dt = new DataTable();
		DataColumn col1 = new DataColumn("Fname", typeof(string));
		DataColumn col2 = new DataColumn("Lname", typeof(string));

		dt.Columns.Add(col1);
		dt.Columns.Add(col2);
		DataRow row = dt.NewRow();
		row["Fname"] = "name1";
		row["Lname"] = "lnamel";
		dt.Rows.Add(row);
		DataRow row2 = dt.NewRow();
		row["Fname"] = "name2";
		row["Lname"] = "lname2";
		dt.Rows.Add(row2);

		grd.DataSource = dt;
		grd.DataBind();
	}
	protected void grd_RowDataBound(object sender, GridViewRowEventArgs e)
	{
		if (e.Row.RowType == DataControlRowType.DataRow)
		{
			Label lblFname = e.Row.FindControl("lblFname") as Label;
			Label lblLname = e.Row.FindControl("lblLname") as Label;
		}
	}

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Hiren Patel | Please click "Propose As Answer" if this post solves your problem or "Vote As Helpful" if this post has been useful to you.

Answer 6

Hi Hiren,

Thanks for the guide. I'm able to generate new row for textbox or label in my gridview but not for the SP datetimepicker. As for the resolution, I have used jQuery datepicker and it solved my issue. 

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wawa87