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Con rispostaGet type of function parameter

  • martedì 26 maggio 2009 8.48shootingsyh Medaglie utenteMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utente
     

    I have an assembly A, which contains some functions:
    void log(Uri u);
    void log(int i);
    void log(CustomType t);

    The CustomType is defined in another assembly B.

    I open the assembly A use PEModuleUnit.Open, then I want to get the parameter types for each log function and add them into a array.

    But I found that the ParameterSymbol.Type doesn't give the expected type.

    I expect the parameter of type uri has the type object32->class64, and the class64 should have symbol of name "System.Uri". But the result is the class64 is a function ClrCall.Function(i32)->(object32->class64) type!!

    Can anyone tell me what happens to the type "Uri"? Thanks

    The same thing happens to the CustomType, just the object32->class64 type, and the class64 type is a ClrCall.Function()->(void)

Risposte

  • martedì 26 maggio 2009 15.34Andy Ayers - MSFTModeratoreMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utente
     Con risposta
    Depending on how you have set the cross-assembly type resolution, you may need to use type.IsReferenceTo(type). By default I believe we preserve the distinction between references and definitions.
    Architect - Microsoft Phoenix Project
    • Contrassegnato come rispostashootingsyh giovedì 10 settembre 2009 2.54
    •  

Tutte le risposte

  • martedì 26 maggio 2009 8.52shootingsyh Medaglie utenteMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utente
     
    The above process happends in some process Phase of assembly B. There are a function called Perform(Uri u, CustomType c) in B. After the above process, I load the function unit of Perform and retrieve it's parameter types. Then I found the type of u in B.Perform is not equal to type of u in A.log. But they are all of type Uri, why the .Equal and all other .IsEqualxxx return false?
  • martedì 26 maggio 2009 15.31Andy Ayers - MSFTModeratoreMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utente
     
    How are you getting the name of the class64 type? It almost looks like you are getting its constructor member's type instead. The name of a type is found on the type symbol for the type.
    Architect - Microsoft Phoenix Project
  • martedì 26 maggio 2009 15.34Andy Ayers - MSFTModeratoreMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utente
     Con risposta
    Depending on how you have set the cross-assembly type resolution, you may need to use type.IsReferenceTo(type). By default I believe we preserve the distinction between references and definitions.
    Architect - Microsoft Phoenix Project
    • Contrassegnato come rispostashootingsyh giovedì 10 settembre 2009 2.54
    •  
  • martedì 16 giugno 2009 6.28shootingsyh Medaglie utenteMedaglie utenteMedaglie utenteMedaglie utenteMedaglie utente
     

    I still cannot get the right type of the parameter. I found the type symbol of that type is just null. I’ve tried to get the type both from the ParameterSymbols and destination operand of function enter instruction, but failed on both of them. Is there some approach I should perform to load the symbol? Since it’s just a Uri class, the symbol should be there.