Does RandBetween in microsoft word exist?
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jueves, 02 de agosto de 2012 2:11
That's pretty much the question. I'm trying to get a code that chooses a random number between -1 and 1.
- Editado tonayie viernes, 03 de agosto de 2012 3:16
Todas las respuestas
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jueves, 02 de agosto de 2012 5:22
There is no such function built in, but you can easily create on yourself:
Function RandBetween(Bottom As Long, Top As Long) As Long RandBetween = Bottom + Int(Rnd * (Top - Bottom + 1)) End Function
and use it like the Excel function.Regards, Hans Vogelaar
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jueves, 02 de agosto de 2012 23:27
i used one from here: http://msdn.microsoft.com/en-us/library/f7s023d2(v=vs.90).aspx
unfortunately, it does nothing for my code.
- Editado tonayie viernes, 03 de agosto de 2012 3:16 code is private
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viernes, 03 de agosto de 2012 1:51
Try:
Randomize Timer
h = CLng(Int((3 * Rnd()) - 1))Note that you may get an error if i=1 and h = -1.
Cheers
Paul Edstein
[MS MVP - Word]- Marcado como respuesta tonayie viernes, 03 de agosto de 2012 2:10
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viernes, 03 de agosto de 2012 2:10
that's amazing, how did you know? it worked very well, perfectly and I've been trying for so long too. where's the negative value? so so amazing, thank you so much.Try:
Randomize Timer
h = CLng(Int((3 * Rnd()) - 1))Note that you may get an error if i=1 and h = -1.
Cheers
Paul Edstein
[MS MVP - Word] -
viernes, 03 de agosto de 2012 3:41
Hi tonayie,
3 * Rnd() produces a number between 0 and 3.
Int(3 * Rnd()) discards the decimal parts and thus returns 0, 1 or 2
Deducting 1 from 0, 1 or 2 returns -1, 0 or 1.Quite simple, really.
Cheers
Paul Edstein
[MS MVP - Word]

