Send File By TcpClient generate SocketException

Sun, 10 Jun 2007 12:24:09 Z

Code Snippet

private void SendFile(string address)
{
TcpClient tClient = new TcpClient(new IPEndPoint(IPAddress.Loopback , TcpPort));

// Generate SocketException

// No connection could be made because the target machine actively refused it

tClient.Connect(IPAddress.Loopback , TcpPort); // ErrorCode=10061

NetworkStream sendNetStm = tClient.GetStream();

FileStream sendFileStm = new FileStream(address, FileMode.Open);

byte[] buffer = new byte[256];
int count;

                while ((count = sendFileStm.Read(buffer, 0, buffer.Length)) != 0)
                {
                    sendNetStm.Write(buffer, 0, count);
                }

                sendFileStm.Close();
                   tClient.Close();
         }

Why?How to solve?

Send File By TcpClient generate SocketException

Mon, 11 Jun 2007 10:05:46 Z

What's the exception?! We're not psychic... :-,) Where does it occur (what's its stack trace)?

However, you should probably change the first line to be TcpClient tClient = new TcpClient();

I presume you have another application listening on port TcpPort, maybe a TcpListener of your own in another program...?

Send File By TcpClient generate SocketException

Mon, 11 Jun 2007 11:09:56 Z

Thanks for your reply,I'v been edit the thread,please help me,and I can't speak English,but I'm learning.

Send File By TcpClient generate SocketException

Tue, 12 Jun 2007 14:18:01 Z

Err... Did you change

TcpClient tClient = new TcpClient(new IPEndPoint(IPAddress.Loopback , TcpPort));

TcpClient tClient = new TcpClient();

Do you still get an exception? Which exception? SocketException, ArgumentException? What line?