Is it possible to convert XML into a Class?

Question

Given an XML stream as below, is there any possibility to convert the same into any treditional class style with . (dots) as seperator of the nodes of the xml file...

for instance

bank.code.tostring() should reslut me "5070" and

bank.description.tostring() should result "ICICI - Bangalore"

bank.location.destination.code should result "MB"

bank.location.zone.code.tostring() should result "12" etc .,

And the XML file being ...

<?xml version="1.0" encoding="utf-8" ?>

<MainBank>

      <bank>

            <code>5070</code>

            <description>ICICI - Bangalore</description>

            <contactPerson>Peter Loke</contactPerson>

            <location>

                  <destination>

                        <code>MB</code>

                        <description>Main Branch at Mayohall</description>

                  </destination>

                  <zone>

                        <code>12</code>

                        <description>Admin building and 8to8Branch</description>

                  </zone>

            </location>

            <catagory>

                  <code>1LL</code>

                  <description>Admin with ExchRout plus Hub</description>

            </catagory>

            <exchContact>E839IRU</exchContact>

            <isTT>true</isTT>

            <classification>F98X</classification>

            <branchDets>

                  <code>8525</code>

                  <description>Administration Branch from 3rd_u70 ?loor Onwards</description>

                  <floors>3,4</floors>

                  <type>FA</type>

                  <description>

                        <detail>Fully Automated</detail>

                        <ATM>True</ATM>

                        <eTT>False</eTT>

                  </description>

                  <offices>

                        <offtype>

                              <code>SA</code>

                              <description>System Admin</description>

                        </offtype>

                        <currency>INR</currency>

                        <frCur>false</frCur>

                  </offices>

            </branchDets>

      </bank>

      <bank>

            <code>5071</code>

            <description>ICICI - Mumbai</description>

            <contactPerson>Jane Edwards</contactPerson>

            <location>

                  <destination>

                        <code>MB</code>

                        <description>Main Branch at VT</description>

                  </destination>

                  <zone>

                        <code>12</code>

                        <description>Admin building and 8to8Branch</description>

                  </zone>

            </location>

            <catagory>

                  <code>1LL</code>

                  <description>Admin with ExchRout plus Hub</description>

            </catagory>

            <exchContact>E839IRU</exchContact>

            <isTT>true</isTT>

            <classification>F98X</classification>

            <branchDets>

                  <code>8525</code>

                  <description>Administration Branch from 3rd_u70 ?loor Onwards</description>

                  <floors>3,4,5,6</floors>

                  <type>FA</type>

                  <description>

                        <detail>Fully Automated</detail>

                        <ATM>True</ATM>

                        <eTT>False</eTT>

                  </description>

                  <offices>

                        <offtype>

                              <code>SA</code>

                              <description>System Admin</description>

                        </offtype>

                        <currency>INR</currency>

                        <currency>USD</currency>

                        <frCur>True</frCur>

                  </offices></branchDets></bank></MainBank>

 

Answer 1

You can write something that generates the class for you and populates it.  If the XML is known and you generate the class first, it will be easier.

 

Answer 2

Any idea about how can i generate the class first... i know the xml.. can you pl, through a little more light ?

Answer 3

 

hi

 i think you cant convert this xml to class, because xml should compatable with Dataset, then only you can convert to class, any this is the tool to convert xml in to class.

xsd.xml

class to schema conversion and schema to class conversion.

 

   -thanks

Answer 4

The xsd.exe is at.

C:\Program Files\Microsoft Visual Studio 8\SDK\v2.0\Bin\xsd.exe

 

You may be able to run it when you run the Visual Studio 2005 Command Prompt.

Answer 5

Unfortunately we are still working with Visual studio 2003. Any othe way?

Answer 6

Hi,

VS2003 is at:

C:\Program Files\Microsoft Visual Studio .NET 2003\SDK\v1.1\Bin\xsd.exe

Answer 7

Thanks ... I could convert .XML into .CS file. But now, the problem is... how can i use this class to extract the xml values?

Answer 8

Use XmlSerializer.

 

http://msdn2.microsoft.com/en-us/library/system.xml.serialization.xmlserializer(VS.80).aspx

 

http://msdn.microsoft.com/library/default.asp?url=/library/en-us/cpref/html/frlrfSystemXmlSerializationXmlSerializerClassTopic.asp

Answer 9

How to Convert XML into a Class?

thank you!!!