XSLT Processor
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Friday, August 10, 2012 1:35 PM
I want to display my XML file as HTML. I have a corresponding XSL file. I have included the reference to the XSL file inthe XML file. I'm using Internet Explorer 8, but when I open the XML file, I just get the XSL file without the data contained in the XML file.
XML:
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="C:\Path\Form1.xsl"?>
<ParameterXml xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Name>Form1</Name>
<Description>Reference</Description>
<Note />
<ValueNote />
<TypeId>12</TypeId>
<DataFileId>0</DataFileId>
</ParameterXml>XSL:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:template match="/">
<html>
<body>
<h2>Parameter: <xsl:value-of select="Name"/></h2>
<h3>Description: <xsl:value-of select="Description"/></h3>
<h3>Note: <xsl:value-of select="Note"/></h3>
<h3>ValueNote: <xsl:value-of select="ValueNote"/></h3>
<h3>TypeId: <xsl:value-of select="TypeId"/></h3>
<h3>DataFileId: <xsl:value-of select="DataFileId"/></h3>
</body>
</html>
</xsl:template></xsl:stylesheet>
Can anyone help me out?
John
All Replies
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Friday, August 10, 2012 3:07 PM
I discovered the problem.
The answer lies in the stylesheet. The Name, Description, Note, ValueNote, TypeId and DataFileId are part of the ParameterXml structure, so I need to specify the path in the <<value-of>> statement. Instead of writing <xsl:value-of select="Name"/>, for example, I should have written <xsl:value-of select="ParameterXml/Name"/>.
John
- Marked As Answer by JohnOnMsdn Friday, August 10, 2012 3:08 PM
