How do I access an attribute from the outer node inside an inner condition?

Question

Hi all;

I want to perform the following XPath: /Configs/Category/InputMenu/Config[@Value = 'DualPack' and (/Configs/Category/MasterSlave/Config[@No = ./@No]/@Value = 'Master')]

Where the "./@No" in the part"[@No = ./@No]" is from /Configs/Category/InputMenu/Config@No, not from /Configs/Category/MasterSlave/Config@No

How can I specify that the ./@No is from that outer node?

thanks - dave

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Who will win The Windward International Collegiate Programming Championships?

Answer 1

Try this:

/Configs/Category/InputMenu/Config[@Value = 'DualPack' and (/Configs/Category/MasterSlave/Config[@No = ../../InputMenu/Config/@No]/@Value = 'Master')]

Morten la Cour

Answer 2

I feel like an idiot - that works great.

thanks

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Who will win The Windward International Collegiate Programming Championships?