Price data per hour

Question

Hello, every one,  i have a question :

. A language (example C#) could compute data/hour so an application needs only a RTSP(in application layer) for bandwidth?

Thank you.

For your information : " I have an example : "Application compute data (data/hour) and be executable over RTSP layer." "

For your information : "I not say that other protocols have no code."

For your information : "The  question about maths posted in http://social.microsoft.com/Forums/en-US/generaldiscussions/thread/9ff8d5ee-3055-459e-94fc-19d0b8ea8a0d"

For your information : "In the above question the example should be in the answer. I not say there is not other example."

Thank you.

---

Mr. Leonidas Fengos Object Oriented Programmer

Answer 1

Hi,

I am not familiar with Nyquist-Shannon sampling theorem. Do you mean you want to calculate some data based on the formula described in http://en.wikipedia.org/wiki/Nyquist%E2%80%93Shannon_sampling_theorem? It seems to use Fourier transform. As far as calculate an approximate value for a definite integral programmatically, you can use the definition of definite integral:

Lim(Sigma(f(xi)*DeltaX))

Divide the region to an infinite number of subintervals, calculate each subinterval’s area, and add them together. One of the solutions is to use a rectangle to emulate each subinterval. Of course we won’t be able to divide the region infinitely. So we can approximate the result by, say use 1000 intervals. It’s easy for a computer to calculate the areas for 1000 rectangles. We can also use Simpson’s Rule which may give us better result (use quadratics instead of rectangles). I am not sure how to calculate Fourier transform as it seems to require calculate a definite integral from negative infinite to positive infinite. But according to http://en.wikipedia.org/wiki/Fourier_transform, in most cases you can use –T/2 and T/2 as the lower/upper bound, so this is essentially a definite integral. And since Fourier transform seems to assume the original function converges between the interval, I “guess” this approximation can work in most cases.

In addition, if you have more questions regarding math, I would recommend you to post a thread on a math forum, there are more related experts in math forums.

 

Best Regards,

Ming Xu.

---

Please mark the replies as answers if they help or unmark if not.
If you have any feedback about my replies, please contact [e-mail].
Microsoft One Code Framework

Answer 2

Hi,

I will mark the reply as an answer. If you find it no help, please feel free to unmark it and follow up.

Thanks.

 

Best Regards,

Ming Xu.

---

Please mark the replies as answers if they help or unmark if not.
If you have any feedback about my replies, please contact [e-mail].
Microsoft One Code Framework