how to check usercontrol is allready invock or not

Question

hello,

in my application i m open a keyboard on textbox click . the keyboard i am creating a custom user control now when i touch on textbox then keyboard open .

the problem is how i check keyboard is already open or not when i touch twice time

---

Dharmesh Sharma [e-mail] www.dharmeshsharma.com

Answer 1

Hello,

This depands on how you show your custom control.

Please provide some more information about this:
Do you show your control in a ScatterViewItem?
If not where do you add it to your visible collection?

You could also think about making your keyboard singleton and give it a "Visible" property.

But your current question does not provide enough information to give an answer.

---

Roy Janssen - Semper IT Services (Please mark an answer as "answered" if it does help you!)

Answer 2

Hello,

this is my code i m try to show my custom control

private void AddressBoxBrowserNumber01_TouchDown(object sender, TouchEventArgs e)
        {


            //ScatterView sv = new ScatterView();
            //ScatterViewItem vi = new ScatterViewItem();
            //sv.Items.Add(vi);
            //vi.SetResourceReference(DependencyProperty.Register("",Type.DefaultBinder,type

            //sv.Items.Add(new UserControl1());

            UserControl1 user_keyboard = new UserControl1();
            user_keyboard.Name = "user1";
            user_keyboard.Visibility = System.Windows.Visibility.Hidden;
            if (user_keyboard.Visibility != Visibility)
            {
                ScatterViewItem svi = new ScatterViewItem();
                svi.Height = 340;
                svi.Width = 1000;
                user_keyboard.Visibility = System.Windows.Visibility.Visible;
                svi.Content = user_keyboard;
                sv.Items.Add(svi);

            }
        }

thanks

i just want to show only one time but int this code i have no idea how to track my custom control that show by this textbox or not

---

Dharmesh Sharma [e-mail] www.dharmeshsharma.com

Answer 3

Hello,

The following code should do the trick.

private void AddressBoxBrowserNumber01_TouchDown(object sender, TouchEventArgs e)
{
    if (sv.Items.OfType<ScatterViewItem>().Count(i => i.Name.StartsWith("Keyboard")) == 0)
    {
        UserControl1 user_keyboard = new UserControl1();
        user_keyboard.Name = "user1";

        ScatterViewItem svi = new ScatterViewItem();
        svi.Height = 340;
        svi.Width = 1000;
        svi.Name = "Keyboard";
        user_keyboard.Visibility = System.Windows.Visibility.Visible;
        svi.Content = user_keyboard;
        sv.Items.Add(svi);
    }
}

I hope this helps you.

---

Roy Janssen - Semper IT Services (Please mark an answer as "answered" if it does help you!)

Answer 4

Hello, Roy Janssen 

But i m trying this same code with two textboxs then not working 

its only work for one so every textbox generate unique  custom contol show how i  mean how to create a unique  name of contol when every 

text box show control

---

Dharmesh Sharma [e-mail] www.dharmeshsharma.com

Answer 5

Hello,

Based on the information you gave until now the previous answer was correct. We can not know what you want if you do not specify it.
If you take a close look at the provided code you can simply change this to your needs...

private void AddressBoxBrowserNumber01_TouchDown(object sender, TouchEventArgs e)
{
    TextBoxTouched("user1");
}

private void AddressBoxBrowserNumber02_TouchDown(object sender, TouchEventArgs e)
{
    TextBoxTouched("user2");
}

private void TextBoxTouched(string textBoxName)
{
    if (sv.Items.OfType<ScatterViewItem>().Count(i => i.Name.StartsWith(textBoxName)) == 0)
    {
        UserControl1 user_keyboard = new UserControl1();
        user_keyboard.Name = "user1";

        ScatterViewItem svi = new ScatterViewItem();
        svi.Height = 340;
        svi.Width = 1000;
        svi.Name = textBoxName;
        user_keyboard.Visibility = System.Windows.Visibility.Visible;
        svi.Content = user_keyboard;
        sv.Items.Add(svi);
    }
}

Hope this helps.

---

Roy Janssen - Semper IT Services (Please mark an answer as "answered" if it does help you!)

Answer 6

yes i m sorry i m not provide correct information 

baiscly i m doing i am add dyamicly add textbox to main window form every textbox touch event i genrate a keyboard 

thats its

but now problem is where i add  ScatterView in main window then my  Custom control textbox how i show keyboard like this 

 if (sv.Items.OfType<ScatterViewItem>().Count(i => i.Name.StartsWith(textBoxName)) == 0)
    {
        UserControl1 user_keyboard = new UserControl1();
        user_keyboard.Name = "user1";

        ScatterViewItem svi = new ScatterViewItem();
        svi.Height = 340;
        svi.Width = 1000;
        svi.Name = textBoxName;
        user_keyboard.Visibility = System.Windows.Visibility.Visible;
        svi.Content = user_keyboard;
        sv.Items.Add(svi);
    }
cos we can add only one ScatterView ?

---

Dharmesh Sharma [e-mail] www.dharmeshsharma.com

Answer 7

what i am doing 

i have main form . Now i have created two custom controls one textbox and keyboard

first i have add textbox by programming when user touch any one textboxs i have to show keyboard contols

so my flow is disturb i don't understand how i do this flow in wpf

thanks

---

Dharmesh Sharma [e-mail] www.dharmeshsharma.com

Answer 8

Hello,

I do not understand your question. You only need one ScatterView in the provided example it is called "sv"

By selecting the textboxes you add a ScatterViewItem to the ScatterView.  You keep adding ScatterViewItem objects to the ScatterView, this is the way to do it. If you need more ScatterView's you could change the code to not only give the textboxname but also the ScatterView to which the ScatterViewItem needs to be added.

I hope this answers your question.

---

Roy Janssen - Semper IT Services (Please mark an answer as "answered" if it does help you!)

Answer 9

Yes sir this is my answer 

i m posting new question with  more info

thanks

---

Dharmesh Sharma [e-mail] www.dharmeshsharma.com

Answer 10

Is your problem solved? Dont forget to mark an answer as "answered".

---

Roy Janssen - Semper IT Services (Please mark an answer as "answered" if it does help you!)