Monday, July 17, 2006 10:39 AM
I think this calculated measure implementation is making me absent minded, so if this seems like a silly question, please ignore my behaviour but do answer to my post :-)
I will ask this question with a sample data: consider that the cube consists of School Children's names as the first dimension (school_children) and date(jan, feb....) as the second dimension. the measure (M) is the 'exam scores' of the school children.
jan feb mar
school_children M M M
tony 50 20 40
bony 10 40 40
mony 60 60 70
Now when i add a calculated measure where I want to display the avg marks of each. so in the calculated measures formula I add: Avg([Measures].[M]). (This is how it is in the Oracle OLAP :-))
But this does not display the average of all tony's scores in a new column M2 (calculated measure). it just displays the same values as the measure M.
so what is happening here? how to get the average then? I do not want to use an avg Aggregation. I thought that I would probably have to programmatically convert all avg functions to something like this: [Measures].[M] / count([Measure].[M]=tony or soemthing like this. not sure again.
Monday, July 17, 2006 12:40 PM
The Avg function receives a set as a first parameter, and the measure you want to calculate the average of as a second.
The second parameter is optional, so in this case you are saying to Analysis Services: "give me the average of the measures in the current query context for the set [Measures].[M]" That is: (Measures].[M] / 1)
Since you want to calculate the avg along the time dimension, you should say:
For mor information on Avg see: