hi The don`t send
Hi,
I have a application for Windows Mobile 6 Pocket PC with framework 3.5 and it gets a lot of this framework error dialog witch says that an error occurred in myApp.exe and it want to send it to Microsoft. You know, the dialog with a left button with caption "Don´t send" and right button with caption "Send".
I don´t understand why I get this while I have Try/Catch everywhere in my code and I also have a global routine that logs the exception to a xml file datatable and send this to a webservice.
The details for the error does not show any stack info and I don´t understand the detail it want to send to Microsoft.
Does anyone has any idea how I can track this down?
Answers
Good Afternoon:
This forum is for software developers who are using the Open Protocol Specification documentation to assist them in developing systems, services, and applications that are interoperable with Windows. The Open Protocol Specifications can be found at: http://msdn2.microsoft.com/en-us/library/cc203350.aspx. Since your post does not appear to be related to the Open Protocol Specification documentation set we would appreciate it if you could try to post your question to one of the forums at the following URL
http://forums.microsoft.com/MSDN/default.aspx?ForumGroupID=11&SiteID=1
instead to find the information you are looking for.
Regards, Obaid Farooqi- Marked As Answer byObaid FarooqiMSFT, ModeratorFriday, January 30, 2009 7:29 PM
All Replies
Good Afternoon:
This forum is for software developers who are using the Open Protocol Specification documentation to assist them in developing systems, services, and applications that are interoperable with Windows. The Open Protocol Specifications can be found at: http://msdn2.microsoft.com/en-us/library/cc203350.aspx. Since your post does not appear to be related to the Open Protocol Specification documentation set we would appreciate it if you could try to post your question to one of the forums at the following URL
http://forums.microsoft.com/MSDN/default.aspx?ForumGroupID=11&SiteID=1
instead to find the information you are looking for.
Regards, Obaid Farooqi- Marked As Answer byObaid FarooqiMSFT, ModeratorFriday, January 30, 2009 7:29 PM


