Another byte manipulation question

Question

Hi, I have another byte manipulation question: What is the effect of the following ? It is in the context of data recieved by a socket.

  sByteCt = 0;
  sByteCt = szBuf[2] & 0xff;
  sByteCt = sByteCt << 8;
  sByteCt = sByteCt | (szBuf[1] & 0xff);

Thanks in advance.

Answer 1

Take the 3rd byte and mask off all but the lower 8 bits (the low byte)
Move those 8 bits to the left 8 bits (so they are now the high byte)
Take the 2nd byte and mask off all but the lower 8 bits and combine this with the result from above.


In other words, make the low byte of the 3rd array element the high byte, and the low byte of the 2nd array element the low byte.

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