How to print windows form in C# application

Question

Dear All,
 I have application,that having one windwos form.on form some images are drawn, I want to print that form on one button click event.
Please help me that code writing.without crystal report and print preview option.

I want to without PrintScreen, windows form printing...

Thanks,

Rajesh.

Answer 1

            Bitmap bitmap = new Bitmap(this.Width, this.Height);
            this.DrawToBitmap(bitmap, this.ClientRectangle);
            bitmap.Save("myPrintScreen.bmp");

this code works on a Windows.Forms-

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Best regards, Sergiu

Answer 2

Hi - I think my information can help.

Well, Sergiu is almost correct, his code will capture the Windows Form application UI.
It will also save it.


Figure A: Using the Sergiu's code example.

==========================================================
try
{
      int x = SystemInformation.WorkingArea.X;
      int y = SystemInformation.WorkingArea.Y;

      int width = this.Width;
      int height = this.Height;

 

      Rectangle bounds = new Rectangle(x, y, width, height);

 

      Bitmap img = new Bitmap(width, height);

 

      this.DrawToBitmap(img, bounds);
      string date = DateTime.Now.ToString("Mdyyyy");
      img.Save(date + ".bmp");
}
catch (Exception ex)
{
    MessageBox.Show(ex.Message.ToString());
}
==========================================================

Here are the results using my above code example:


Figure B: It will capture the entire form, all form bounds.

I hope this information was helpful....

Have a nice day...

Best regards,
Fisnik

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Coder24.com

Answer 3

But how can i print that img, on button click event without showing user

Answer 4

Hi again:

It will never be shown to the user.

What do you mean by that?

I mean the file is getting saved in a directory.

Have a nice day...

Best regards,
Fisnik

---

Coder24.com

Answer 5

Hi
  I have form that having print button, if user click button that time print command will fire.
so please give me that code.

thanks
Rajesh

Answer 6

Check out my replay, the earlier one.

That one with screenshots.

Have a nice day...

Best regards,
Fisnik

---

Coder24.com

Answer 7

Hi,

this is the code-snippet:
===============================================================
try
{
      int x = SystemInformation.WorkingArea.X;
      int y = SystemInformation.WorkingArea.Y;
       int width = this.Width;
      int height = this.Height; 

     Rectangle bounds = new Rectangle(x, y, width, height); 

     Bitmap img = new Bitmap(width, height); 

       this.DrawToBitmap(img, bounds);
      string date = DateTime.Now.ToString("Mdyyyy");
      img.Save(date + ".bmp");
}
catch (Exception ex)
{
    MessageBox.Show(ex.Message.ToString());
}
===============================================================

Have a nice day...

Best regards,
Fisnik

---

Coder24.com

Answer 8

You are a little lazy, man :)

You just have to print the resulting image.

Like this:

protected void btnPrint_Click(object sender, EventArgs e)
{
	PrintDocument pd = new PrintDocument();
	pd.PrintPage += new PrintPageEventHandler(PrintImage);
	pd.Print();      
}

void PrintImage(object o, PrintPageEventArgs e)
{
	int x = SystemInformation.WorkingArea.X;
	int y = SystemInformation.WorkingArea.Y;
	int width = this.Width;
	int height = this.Height; 

	Rectangle bounds = new Rectangle(x, y, width, height); 

	Bitmap img = new Bitmap(width, height); 

	this.DrawToBitmap(img, bounds);
	Point p = new Point(100, 100);
	e.Graphics.DrawImage(img, p);    
 }

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Best regards, Sergiu

Answer 9

Hello Sir,

I try this, showing me this error, it might be some another problem but if you can help....

Error 1 Unable to copy file "obj\Debug\AdityaConsultants.exe" to "bin\Debug\AdityaConsultants.exe". The process cannot access the file 'bin\Debug\AdityaConsultants.exe' because it is being used by another process. WindowsApplication1

Thanks

Anas

Answer 10

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Drawing.Imaging;
using System.IO;
using System.Drawing.Printing;
using System.Runtime.InteropServices;

namespace fro
{
public partial class print : Form
{
private System.IO.Stream streamToPrint;
string streamType;
[System.Runtime.InteropServices.DllImportAttribute("gdi32.dll")]
private static extern bool BitBlt
(
IntPtr hdcDest,
int nXDest,
int nYDest,
int nWidth,
int nHeights,
IntPtr hdcSrc,
int nXSrc,
int nYSrc,
System.Int32 dwRop
);

public print()
{
InitializeComponent();
printDocument1.PrintPage += new PrintPageEventHandler(printDocument1_PrintPage);
}







private void printDocument1_PrintPage(System.Object sender, System.Drawing.Printing.PrintPageEventArgs e)
{
System.Drawing.Image image = System.Drawing.Image.FromStream(this.streamToPrint);
int x = e.MarginBounds.X;
int y = e.MarginBounds.Y;
int width = image.Width;
int height = image.Height;
if ((width / e.MarginBounds.Width) > (height / e.MarginBounds.Height))
{
width = e.MarginBounds.Width;
height = image.Height * e.MarginBounds.Width / image.Width;
}
else
{
height = e.MarginBounds.Height;
width = image.Width * e.MarginBounds.Height / image.Height;
}
System.Drawing.Rectangle destRect = new System.Drawing.Rectangle(x, y, width, height);
e.Graphics.DrawImage(image, destRect, 0, 0, image.Width, image.Height, System.Drawing.GraphicsUnit.Pixel);
}


public void StartPrint(Stream streamToPrint, string streamType)
{
this.printDocument1.PrintPage += new PrintPageEventHandler(printDocument1_PrintPage);
this.streamToPrint = streamToPrint;
this.streamType = streamType;
System.Windows.Forms.PrintDialog printDialog1 = new PrintDialog();
printDialog1.AllowSomePages = true;
printDialog1.ShowHelp = true;
printDialog1.Document = printDocument1;
DialogResult result = printDialog1.ShowDialog();
if (result == DialogResult.OK)
{
printDocument1.Print();

}

}

private void print_Load(object sender, EventArgs e)
{
this.Load += new System.EventHandler(this.print_Load);
}

private void button1_Click(object sender, EventArgs e)
{
MessageBox.Show("errr");
Graphics g1 = this.CreateGraphics();
Image MyImage = new Bitmap(this.ClientRectangle.Width, this.ClientRectangle.Height, g1);
Graphics g2 = Graphics.FromImage(MyImage);
IntPtr dc1 = g1.GetHdc();
IntPtr dc2 = g2.GetHdc();
BitBlt(dc2, 0, 0, this.ClientRectangle.Width, this.ClientRectangle.Height, dc1, 0, 0, 13369376);
g1.ReleaseHdc(dc1);
g2.ReleaseHdc(dc2);
MyImage.Save(@"C:\PrintPage.jpg", ImageFormat.Jpeg);
FileStream filestream = new FileStream(@"C:\PrintPage.jpg", FileMode.Open, FileAccess.Read);
StartPrint(filestream, "Image");
if (System.IO.File.Exists(@"c:\PrintPage.jpg"))
{
System.IO.File.Delete(@"C:\PrintPage.jpg");
}
else
MessageBox.Show("errr");
}

private void InitializeComponent()
{
this.printDocument1 = new System.Drawing.Printing.PrintDocument();
this.SuspendLayout();
// //
// // Form1
// //
this.ClientSize = new System.Drawing.Size(292, 266);
this.Name = "print";
this.Load += new System.EventHandler(this.print_Load);
this.ResumeLayout(false);

}


}


}

Answer 11

Your code function, but you have open this file with an other application. Close this application and try again. That will be good

Clémox

Answer 12

Hi Fisnik,

Just wondering where it is the image saves itself?

 

Kind Regards

Sam Mines

---

Sam Mines

Answer 13

can u rotate the image in landscape mode while printing

because my image size is 950*665