How to convert _timeb time into C# DateTime object

Question

My program references a datafile that has record times listed as timebuffer.time in C++.  This is the code that sets the time from the C++ side:

struct _timeb timebuffer;
unsigned int Time;
 _ftime (&timebuffer);
 DX_data.Time  = (unsigned int)timebuffer.time;


i would like to read that in on my side (C#) and output it my appropriate format.  Could someone help me out with this?
THanks,

Answer 1

You can do this by creating a timespan and adding it to the reference time.  It sounds like you're doing this in C++, in which case, it'd be:

// using namespace System;

struct _timeb timebuffer;
_ftime(&timebuffer);

TimeSpan ts = TimeSpan(0,0,0, timebuffer.time, timebuffer.millitm);
DateTime refTime = DateTime(1970,1,1);
DateTime finalTime = refTime + ts;

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Reed Copsey, Jr. - http://reedcopsey.com

Answer 2

I'm doing it in C#.  I tried it in the C# code, and that is what i am looking for.  Thanks!

Answer 3

Hi,
We need a c++ method that returns the timebuffer.time , so that we can get the time value in C# code.
If you already have, do you mind post the method signature?

Thanks,
Eric

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Answer 4

My previous answer showed you C++ code to get timebuffer.time. The call is _ftime:

    struct _timeb timebuffer;
    _ftime(&timebuffer);

    time_t time = timebuffer.time;

That's all there is to it.

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Reed Copsey, Jr. - http://reedcopsey.com