Deserialization of this XML

Question

Hello,

What would be the class definition to deserialize the following XML into ..

<?xml version="1.0" encoding="UTF-8"?>

<response xmlns="http://schemas.persony.com/wc2/rest/1.0">

	<sessions start='[START]' next='[NEXT]'>

<!--BEGIN_SESSIONS-->

		<session in_progress='[IN_PROGRESS]'>

			<session_id>[SESSION_ID]</session_id>

			<host_login>[HOST_LOGIN]</host_login>

			<meeting_id>[MEETING_ID]</meeting_id>

			<meeting_title>[MEETING_TITLE]</meeting_title>

			<start_time>[START_TIME]</start_time>

			<end_time>[END_TIME]</end_time>

			<account_type>[ACCOUNT_TYPE]</account_type>

			<client_data>[CLIENT_DATA]</client_data>

		</session>

<!--END_SESSIONS-->

	</sessions>

</response>

I am trying the following ...

[XmlRootAttribute("response", Namespace = "http://schemas.persony.com/wc2/rest/1.0")]
public class sessions
{
    [XmlElement(ElementName = "session_id")]
    public string session_id { get; set; }

    [XmlElement(ElementName = "host_login")]
    public string host_login { get; set; }

    [XmlElement(ElementName = "meeting_id")]
    public string meeting_id { get; set; }

    [XmlElement(ElementName = "meeting_title")]
    public string meeting_title { get; set; }

    [XmlElement(ElementName = "start_time")]
    public string start_time { get; set; }

    [XmlElement(ElementName = "end_time")]
    public string end_time { get; set; }

    [XmlElement(ElementName = "max_concurrent")]
    public string max_concurrent { get; set; }

    [XmlElement(ElementName = "account_type")]
    public string account_type { get; set; }

    [XmlElement(ElementName = "client_data")]
    public string client_data { get; set; }

}

And the following returns an object with null properties

            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(requestUri);
            HttpWebResponse response = (HttpWebResponse)request.GetResponse();

            try
            {
                XmlSerializer ser = new XmlSerializer(typeof(sessions));
                return (sessions)ser.Deserialize(response.GetResponseStream());
            }
            catch(Exception e)
            {
                string err;
                err =  e.InnerException.ToString();
                return null;
            }

Thanks, Ken

Answer 1

Hi,ken,you should define some more classes

[XmlRoot(''response")]
[Serializable]
public class MyResponse
{
[XmlElement("sessions")]
public Sessions Sessions;
}

[Serializable]
public class  Sessions
{
[XmlAttribute("start")]
public string Start;
[XmlAttribute("next")]
public string Next;

[XmlElement("session",Type=typeof(session))]
public session Session;
}

[Serializable]
public class session
{
    [XmlAttribute("in_progress")]
    public string in_progress;
    [XmlElement(ElementName = "session_id")]
    public string session_id { get; set; }

    [XmlElement(ElementName = "host_login")]
    public string host_login { get; set; }

    [XmlElement(ElementName = "meeting_id")]
    public string meeting_id { get; set; }

    [XmlElement(ElementName = "meeting_title")]
    public string meeting_title { get; set; }

    [XmlElement(ElementName = "start_time")]
    public string start_time { get; set; }

    [XmlElement(ElementName = "end_time")]
    public string end_time { get; set; }

    [XmlElement(ElementName = "max_concurrent")]
    public string max_concurrent { get; set; }

    [XmlElement(ElementName = "account_type")]
    public string account_type { get; set; }

    [XmlElement(ElementName = "client_data")]
    public string client_data { get; set; }

}

Then deserialize as follow:

 HttpWebRequest request = (HttpWebRequest)WebRequest.Create(requestUri);
            HttpWebResponse response = (HttpWebResponse)request.GetResponse();

            try
            {
                XmlSerializer ser = new XmlSerializer(typeof(MyResponse));
                return (MyResponse)ser.Deserialize(response.GetResponseStream());
            }
            catch(Exception e)
            {
                string err;
                err =  e.InnerException.ToString();
                return null;
            }

if sessions element is a collection of session,you should make some change.

---

Wenn ich dich hab’,gibt es nichts, was unerträglich ist.坚持不懈！My blog~~~

Answer 2

Thanks Raymond, that helps.
The sessions element is a collection of sessions.
I have modified the sessions class:

[Serializable]
public class sessions
{
    [XmlAttribute("start")]
    public string Start;
    [XmlAttribute("next")]
    public string Next;

    [XmlElement("session", Type = typeof(List<session>))]
    public List<session> Session;
}

But the list does not populate. Any ideas?

Thanks,
Ken

Answer 3

Hi,Ken
if it is a collection of session entity,then you should make some change as follow:

[Serializable]
public class  Sessions
{
[XmlAttribute("start")]
public string Start;
[XmlAttribute("next")]
public string Next;

 [XmlArray("mySessions")]
 [XmlArrayItem("session", Type = typeof(session))]
public session[] Session;
}


now the xml should changed to


<sessions start='[START]' next='[NEXT]'>

<mySessions>
<!--BEGIN_SESSIONS-->

<session in_progress='[IN_PROGRESS]'>
<session_id>[SESSION_ID]</session_id>

<host_login>[HOST_LOGIN]</host_login>

<meeting_id>[MEETING_ID]</meeting_id>

<meeting_title>[MEETING_TITLE]</meeting_title>

<start_time>[START_TIME]</start_time>

<end_time>[END_TIME]</end_time>

<account_type>[ACCOUNT_TYPE]</account_type>

<client_data>[CLIENT_DATA]</client_data>

</session>

<!--END_SESSIONS-->
</mySessions>

 </sessions>


if you want to keep the current xml structure,you should make an effort.

you should implement IXmlSerializable interface.
here are some examples:
http://www.codeproject.com/KB/XML/yaxlib.aspx#h3formatcol

http://www.codeproject.com/KB/XML/IXmlSerializable.aspx?display=Print

---

Wenn ich dich hab’,gibt es nichts, was unerträglich ist.坚持不懈！My blog~~~