Data set Table Single Column Write To xml
-
1. srpna 2012 3:38
hi experts,
From a Data set Table named receipts i wanted a column named "ui" of type GUID to be exported as an xml.
above XML i want to pass as a parameter to fetch record from "receiptdetails" tables
can some one help me how to do this
- Přesunutý Allen Li - AI3Microsoft Contingent Staff, Moderator 3. srpna 2012 9:49 (From:ADO.NET DataSet)
Všechny reakce
-
1. srpna 2012 15:22
Please check the following example. I was convert a single column from DataTable to xml. Modify this as per your business requirement.
DataTable dtRoleFunction = new DataTable("Role_Function "); dtRoleFunction.Columns.Add("RoleId", typeof(int)); dtRoleFunction.Columns.Add("FunctionId", typeof(int)); dtRoleFunction.Rows.Add(1, 1); dtRoleFunction.Rows.Add(2, 2); dtRoleFunction.Rows.Add(3, 3); dtRoleFunction.Rows.Add(4, 1); dtRoleFunction.Rows.Add(5, 4); var xEle = new XElement("FunctionID", from dt in dtRoleFunction.AsEnumerable() select new XElement("FUN",dt.Field<int>("FunctionId").ToString()));With Thanks and Regards
Sambath Raj.C
click "Proposed As Answer by" if this post solves your problem or "Vote As Helpful" if a post has been useful to you
Happy Programming! -
1. srpna 2012 17:47
Thanks Sambath Raj.C,
Really this was the short and sweet code, and it wrote a xml for me.
i got the result like below
'<Receiptsui> <ui>3501d989-308c-481c-8b2a-f92230d3f9bc</ui> <ui>da832de7-b719-43bb-bfd6-e386eb6dbbda</ui> <ui>11c26563-acb0-4aac-aabd-ef12022feae6</ui> <ui>2e200248-8755-41e9-8be2-922422110443</ui> <ui>e77dffa1-5be9-4671-a819-9ec77060b993</ui> <ui>c507433b-2d05-4f8d-beb3-12bcc5fc66b2</ui> </Receiptsui>'
but now there is a problem i want to read xml output as
DECLARE @xml xml SET @xml= '<Receiptsui> <ui>3501d989-308c-481c-8b2a-f92230d3f9bc</ui> <ui>da832de7-b719-43bb-bfd6-e386eb6dbbda</ui> <ui>11c26563-acb0-4aac-aabd-ef12022feae6</ui> <ui>2e200248-8755-41e9-8be2-922422110443</ui> <ui>e77dffa1-5be9-4671-a819-9ec77060b993</ui> <ui>c507433b-2d05-4f8d-beb3-12bcc5fc66b2</ui> </Receiptsui>' SELECT T.n.value('@ui[1]', 'uniqueidentifier') [ui] FROM @xml.nodes('/Receiptsui/ui') T(n) GO
i am getting null values,how can i solve this
- Upravený Sushil Agarwal 3. srpna 2012 14:21 typing error
-
3. srpna 2012 14:50
Wbob Has given the solution.
replacing '@ui[1]' with '.' after T.n.values i got the result.
thanks to forum experts like wBob & Sambath Raj.C. they spend so much of time and effort to help people like me.
- Označen jako odpověď Sushil Agarwal 3. srpna 2012 14:50
-
8. září 2012 11:18
Dear Sambath Raj.C
var xEle = new XElement("Receiptsui", from dt in ds.Tables["billwithitem"].AsEnumerable() select new XElement("ui", dt.Field<Guid>("ui").ToString()));as suggested by you the i could get the result & thanks a lot for the same.
can u please further tell me if i want distinct rows how do i modify the Qury
because i tried following , still it gives all rows without giving me disitinct rows
var xEle = new XElement("Receiptsui", (from dt in ds.Tables["billwithitem"].AsEnumerable() select new XElement("ui", dt.Field<Guid>("ui").ToString())).Distinct());