I want to change textbox1 which is in the usercontrol

Question

I have a button in Mainwindow.xaml. Its name is ( button1).

In the Mainwindow.xaml there is a usercontrol which is loading dynamically.

I want to change textbox1  which is  in the usercontrol;  when i click (button1).

İ tried the way below but it does not work.

        private void button1_Click(object sender, RoutedEventArgs e)

        {

            UserControl altmenu = new alt_menu();

            ((TextBox)altmenu.FindName("textbox1")).Text = "Hi";

        }

 

I will be happy if you help.

Answer 1

I would recommend exposing a property (as a string) in your UserControl, and setting the textbox Text within the property's setter.  This will help make it easier later if you want to change the internal implementation.

---

Reed Copsey, Jr. - http://reedcopsey.com
If a post answers your question, please click "Mark As Answer" on that post and "Mark as Helpful".

Answer 2

I think, if I understand you, you have a UserControl called "alt_menu"
That has a control which you gave an x:Name to.
Then you can access it directly.
The mistake I think you made was casting it as a UserContrtol, so it lost all identity.

        private void button1_Click(object sender, RoutedEventArgs e)
        {
            var altmenu = new alt_menu();
            altmenu.textbox1.Text = "Hi";
        }

 
Regards,
Pete

---

#PEJL

Answer 3

I would recommend exposing a property (as a string) in your UserControl, and setting the textbox Text within the property's setter.  This will help make it easier later if you want to change the internal implementation.

---

---

thank you for your help, but i can't understand because of my poor English. can you explain this with an example?

        private void button1_Click(object sender, RoutedEventArgs e)
        {
            var altmenu = new alt_menu();
            altmenu.textbox1.Text = "Hi";
        }

 

thank you for your help but this code did not work.

I added usercontrol to Mainwindow.xaml as you see below.

LayoutRoot.Children.Insert(0, altmenu);

Answer 4

If you added altmenu that way - you have to access that one, not create a new one:

 private void button1_Click(object sender, RoutedEventArgs e)
{
    alt_menu altmenu = LayoutRoot.Children[0] as alt_menu;
    ((TextBox)altmenu.FindName("textbox1")).Text = "Hi";
}

---

Reed Copsey, Jr. - http://reedcopsey.com
If a post answers your question, please click "Mark As Answer" on that post and "Mark as Helpful".

Answer 5

My original suggestion was trying to provide a solution that matched your methods...

<Window x:Class="WpfApplication52.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="350" Width="525" Background="#FFF1EEEE">
    <Grid x:Name="LayoutRoot"/>
</Window>

using System.Windows;

namespace WpfApplication52
{
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

            var test = new UserControl1();
            test.test1.Text = "asd";
            LayoutRoot.Children.Add(test);
        }
    }
}

<UserControl x:Class="WpfApplication52.UserControl1"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
    <Grid>
        <TextBox x:Name="test1"/>
    </Grid>
</UserControl>

 

 

Here is Reed's way of doing it, which I agree is the better:

using System.Windows;

namespace WpfApplication52
{
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

            var test = new UserControl1 { UserName = "Reed" };
            LayoutRoot.Children.Add(test);
        }
    }
}

using System.Windows;
using System.Windows.Controls;

namespace WpfApplication52
{
    public partial class UserControl1 : UserControl
    {
        public string UserName
        {
            get { return (string)GetValue(UserNameProperty); }
            set { SetValue(UserNameProperty, value); }
        }

        public static readonly DependencyProperty UserNameProperty =
            DependencyProperty.Register("UserName", typeof(string), typeof(UserControl1), new UIPropertyMetadata(null));

        public UserControl1()
        {
            InitializeComponent();
            DataContext = this;
        }
    }
}

<UserControl x:Class="WpfApplication52.UserControl1"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
>
    <Grid>
        <TextBox Text="{Binding UserName}"/>
    </Grid>
</UserControl>

Hope that helps you understand the two methods.

Regards,
Pete

---

#PEJL

Answer 6

If you added altmenu that way - you have to access that one, not create a new one:

 private void button1_Click(object sender, RoutedEventArgs e)
{
    alt_menu altmenu = LayoutRoot.Children[1] as alt_menu;
    ((TextBox)altmenu.FindName("textbox1")).Text = "Hi";
}

 thanks, thanks, thanks

Answer 7

My original suggestion was trying to provide a solution that matched your methods...

<Window x:Class="WpfApplication52.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="350" Width="525" Background="#FFF1EEEE">
    <Grid x:Name="LayoutRoot"/>
</Window>

using System.Windows;

namespace WpfApplication52
{
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

            var test = new UserControl1();
            test.test1.Text = "asd";
            LayoutRoot.Children.Add(test);
        }
    }
}

<UserControl x:Class="WpfApplication52.UserControl1"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
    <Grid>
        <TextBox x:Name="test1"/>
    </Grid>
</UserControl>

 

 

Here is Reed's way of doing it, which I agree is the better:

using System.Windows;

namespace WpfApplication52
{
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

            var test = new UserControl1 { UserName = "Reed" };
            LayoutRoot.Children.Add(test);
        }
    }
}

using System.Windows;
using System.Windows.Controls;

namespace WpfApplication52
{
    public partial class UserControl1 : UserControl
    {
        public string UserName
        {
            get { return (string)GetValue(UserNameProperty); }
            set { SetValue(UserNameProperty, value); }
        }

        public static readonly DependencyProperty UserNameProperty =
            DependencyProperty.Register("UserName", typeof(string), typeof(UserControl1), new UIPropertyMetadata(null));

        public UserControl1()
        {
            InitializeComponent();
            DataContext = this;
        }
    }
}

<UserControl x:Class="WpfApplication52.UserControl1"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
>
    <Grid>
        <TextBox Text="{Binding UserName}"/>
    </Grid>
</UserControl>

Hope that helps you understand the two methods.

Regards,
Pete

---

#PEJL

XAML guy Thank you for everything

Answer 8

First you should load the usercontrol and then try: for ex:

UserControl altmenu = new alt_menu();

stackPanel.Children.Add(altmenu);

use VisualTreeHelper class to find children, it will solve your problem

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